One possible implementation could be:

function range() {
  const length = arguments.length;

  // early escape conditions
  // if no arguments or
  // single argument provide with value as 0
  // then return empty array
  if (!length || (length === 1 &amp;&amp; arguments[0] === 0)) {
    return [];
  }

  let start = 0;
  let end;
  let step;

  // destructuring variables
  if (length === 3) {
    [start, end, step] = arguments;
  } else if (length === 2) {
    [start, end] = arguments;
  } else {
    [end] = arguments;
  }

  // checking if step is provided or not
  const isStepMissing = step === undefined;

  // if end &lt; start =&gt; -4 &lt; 0
  // and step is missing then default step should be -1
  if (end &lt; start &amp;&amp; isStepMissing) {
    step = -1;
  } else if (isStepMissing) {
    // else default step should be 1
    step = 1;
  }
  
  // if step is not missing then use the provided step
  
  const result = [];

  let i = 0;

  // calculate limit with fail safe check
  let limit = Math.abs(end) / Math.abs(step || 1) - start;

  // loop till iterator &lt; limit
  while (i &lt; limit) {
    // push the current value
    result.push(start + i * step);
    i += 1;
  }

  // return the final resulting array
  return result;
}

Do you see value in our efforts?

Implement a function to generate a range of numbers | Range I | JavaScript Interview Question | Lodash Polyfills

@Devtools Tech